Python Program to check Armstrong Number

Configurare noua (How To)

Situatie

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.

abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + .... 

Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153

Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9

Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723

Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634



									
Solutie

						
# Python program to determine whether


# the number is Armstrong number or not


 


# Function to calculate x raised to 


# the power y


def power(x, y):


     


    if y == 0:


        return 1


    if y % 2 == 0:


        return power(x, y // 2) * power(x, y // 2)


         


    return x * power(x, y // 2) * power(x, y // 2)


 


# Function to calculate order of the number


def order(x):


 


    # Variable to store of the number


    n = 0


    while (x != 0):


        n = n + 1


        x = x // 10


         


    return n


 


# Function to check whether the given 


# number is Armstrong number or not


def isArmstrong(x):


     


    n = order(x)


    temp = x


    sum1 = 0


     


    while (temp != 0):


        r = temp % 10


        sum1 = sum1 + power(r, n)


        temp = temp // 10


 


    # If condition satisfies


    return (sum1 == x)


 


# Driver code


x = 153


print(isArmstrong(x))


 


x = 1253


print(isArmstrong(x))



																																																												
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