Situatie

In this program, a structure Distance containing two data members (inch and feet) is declared to store the distance in the inch-feet system.Here, two structure variables d1 and d2 are created to store the distance entered by the user. And, the sum variable stores the sum of the distances.

Backup

#include <iostream>
using namespace std;

struct Distance {
    int feet;
    float inch;
}d1 , d2, sum;

int main() {
    cout << "Enter 1st distance," << endl;
    cout << "Enter feet: ";
    cin >> d1.feet;
    cout << "Enter inch: ";
    cin >> d1.inch;

    cout << "\nEnter information for 2nd distance" << endl;
    cout << "Enter feet: ";
    cin >> d2.feet;
    cout << "Enter inch: ";
    cin >> d2.inch;

    sum.feet = d1.feet+d2.feet;
    sum.inch = d1.inch+d2.inch;

    // changing to feet if inch is greater than 12
    if(sum.inch > 12) {
        // extra feet
        int extra = sum.inch / 12;

        sum.feet += extra;
        sum.inch -= (extra * 12);
    } 

    cout << endl << "Sum of distances = " << sum.feet << " feet  " << sum.inch << " inches";
    return 0;
}

Output

Enter 1st distance,
Enter feet: 6
Enter inch: 3.4

Enter information for 2nd distance
Enter feet: 5
Enter inch: 10.2

Sum of distances = 12 feet  1.6 inches

Solutie

Tip solutie

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